4(3^x+1)-3^2x=20

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Solution for 4(3^x+1)-3^2x=20 equation: 



4(3^x+1)-3^2x=20

We move all terms to the left:

4(3^x+1)-3^2x-(20)=0

We multiply parentheses

12x-3^2x+4-20=0

We add all the numbers together, and all the variables

12x-3^2x-16=0

We move all terms containing x to the left, all other terms to the right

12x-3^2x=16

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